document.write( "Question 1099379: If cosx=-3/5, and x is in between 180 and 360 degrees, find the value of sinx \n" ); document.write( "
Algebra.Com's Answer #713814 by Boreal(15235)\"\" \"About 
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cos x is negative in the third quadrant, not the fourth, and sin x is negative in the third quadrant.
\n" ); document.write( "cos^2x + sin ^2 x=1
\n" ); document.write( "Therefore, sin ^2 x=1=9/25=16/25
\n" ); document.write( "sin x=-4/5
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