document.write( "Question 1099320: X+6y+20z=200 then find the values of x,y&z? \n" ); document.write( "
Algebra.Com's Answer #713762 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
X+6y+20z=200 then find the values of x,y&z?
\n" ); document.write( "---------
\n" ); document.write( "You can pick values for 2 variables, then find the 3rd.
\n" ); document.write( "eg, x = y = 0
\n" ); document.write( "z = 10
\n" ); document.write( "---
\n" ); document.write( "x = 20
\n" ); document.write( "y = 10
\n" ); document.write( "z = 120
\n" ); document.write( "===========
\n" ); document.write( "There are an infinite # of solutions.
\n" ); document.write( "
\n" );