document.write( "Question 1099320: X+6y+20z=200 then find the values of x,y&z? \n" ); document.write( "
Algebra.Com's Answer #713762 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! X+6y+20z=200 then find the values of x,y&z? \n" ); document.write( "--------- \n" ); document.write( "You can pick values for 2 variables, then find the 3rd. \n" ); document.write( "eg, x = y = 0 \n" ); document.write( "z = 10 \n" ); document.write( "--- \n" ); document.write( "x = 20 \n" ); document.write( "y = 10 \n" ); document.write( "z = 120 \n" ); document.write( "=========== \n" ); document.write( "There are an infinite # of solutions. \n" ); document.write( " |