document.write( "Question 1099314: Determine graphically,the co-ordinates of the vertices of th triangle bounded by 2x-3y+6=0;2x+3y-18=0;y-2=0 Also find the area of this triangle
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #713758 by KMST(5328)![]() ![]() You can put this solution on YOUR website! Determining graphically means we have to start by graphing. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The other two lines can be esily graphed using their x- and y-intercepts. \n" ); document.write( "Once the intercepts for a line are found, \n" ); document.write( "we just plot the points, and draw a line through them. \n" ); document.write( " \n" ); document.write( "has x- and y-intercepts (-3,0) and (0,2) respectively, \n" ); document.write( "that can be found by susbtituting 0 for y and x respectively. \n" ); document.write( "The x- and y-intercepts for \n" ); document.write( " \n" ); document.write( "can be similarly found to be (9,0) and (0,6) . \n" ); document.write( " \n" ); document.write( "From the graph it looks like the vertices of the triangle are (0,2) , (3,4) , and (6,2) . \n" ); document.write( "With the graph, it is easy to see that triangle as one with \n" ); document.write( "a horizontal base of length \n" ); document.write( "and a vertical height \n" ); document.write( "Then, the area of the triangle can be calculated as \n" ); document.write( " \n" ); document.write( "DO WE NEED TO REMEMBER THE FORMULA FOR THE AREA OF A TRIANGLE, AND DO THE CALCULATION? \n" ); document.write( "Not really. It is obvious that the triangle is half of the rectangle outlined below, so we could just count squares: one rectangle = 12 squares, one hald rectangle = 6 squares. \n" ); document.write( " \n" ); document.write( "WHAT IF THE TEACHER WANTS YOU TO SHOW MORE WORK? \n" ); document.write( "I see two places where you would have to show that you really understand how to figure out the problem: \n" ); document.write( " \n" ); document.write( "1) Any side of a triangle (a segment between two vertices) can be called the base, and then the perpendicular distance to the other vertex is the height. \n" ); document.write( "In this case it is easiest to call the horizontal segment between (0,2) and (6,2) the base of the triangle, \n" ); document.write( "and then the vertical distance from that base to point (3,4) would be the height. \n" ); document.write( "Theoretically you would calculate the length of the horizontal base as the difference in x-coordinates of the endpoints of that base, so \n" ); document.write( "Theoretically you would calculate the vertical height as the difference in y-coordinates between the base, and the other vertex, so \n" ); document.write( " \n" ); document.write( "2) Would your teacher insist that you verify the coordinates with some calculations? \n" ); document.write( "Maybe we should really verify that the lines intersect at points with exactly those coordinates, \n" ); document.write( "by substituting those coordinates into the equations of the lines, \n" ); document.write( "because sometimes things are not quite exactly the way they look. \n" ); document.write( "We do not need to verify (0,2) , \n" ); document.write( "which we have shown above that is a point that \n" ); document.write( "is part of blue line \n" ); document.write( "is part of red line \n" ); document.write( "Substituting \n" ); document.write( "we see that it is indeed a solution of \n" ); document.write( "Substituting \n" ); document.write( "we see that it is indeed a solution of |