document.write( "Question 1099314: Determine graphically,the co-ordinates of the vertices of th triangle bounded by 2x-3y+6=0;2x+3y-18=0;y-2=0 Also find the area of this triangle
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Algebra.Com's Answer #713758 by KMST(5328)\"\" \"About 
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Determining graphically means we have to start by graphing.
\n" ); document.write( "\"blue%28y-2=0%29\" <---> \"blue%28y=2%29\" is easy to graph:
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\n" ); document.write( "The other two lines can be esily graphed using their x- and y-intercepts.
\n" ); document.write( "Once the intercepts for a line are found,
\n" ); document.write( "we just plot the points, and draw a line through them.
\n" ); document.write( "\"red%282x-3y%2B6=0%29\" <--> \"red%282x-3y=-6%29\"
\n" ); document.write( "has x- and y-intercepts (-3,0) and (0,2) respectively,
\n" ); document.write( "that can be found by susbtituting 0 for y and x respectively.
\n" ); document.write( "The x- and y-intercepts for
\n" ); document.write( "\"green%282x%2B3y-18=0%29\" <--> \"green%282x%2B3y=18%29\"
\n" ); document.write( "can be similarly found to be (9,0) and (0,6) .
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\n" ); document.write( "From the graph it looks like the vertices of the triangle are (0,2) , (3,4) , and (6,2) .
\n" ); document.write( "With the graph, it is easy to see that triangle as one with
\n" ); document.write( "a horizontal base of length \"b=6\" ,
\n" ); document.write( "and a vertical height \"h=2\" .
\n" ); document.write( "Then, the area of the triangle can be calculated as \"b%2A2%2F2=6%2A2%2F2=Highlight%286%29\" .
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\n" ); document.write( "DO WE NEED TO REMEMBER THE FORMULA FOR THE AREA OF A TRIANGLE, AND DO THE CALCULATION?
\n" ); document.write( "Not really. It is obvious that the triangle is half of the rectangle outlined below, so we could just count squares: one rectangle = 12 squares, one hald rectangle = 6 squares. .
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\n" ); document.write( "WHAT IF THE TEACHER WANTS YOU TO SHOW MORE WORK?
\n" ); document.write( "I see two places where you would have to show that you really understand how to figure out the problem:
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\n" ); document.write( "1) Any side of a triangle (a segment between two vertices) can be called the base, and then the perpendicular distance to the other vertex is the height.
\n" ); document.write( "In this case it is easiest to call the horizontal segment between (0,2) and (6,2) the base of the triangle,
\n" ); document.write( "and then the vertical distance from that base to point (3,4) would be the height.
\n" ); document.write( "Theoretically you would calculate the length of the horizontal base as the difference in x-coordinates of the endpoints of that base, so \"base=6-0=6\" .
\n" ); document.write( "Theoretically you would calculate the vertical height as the difference in y-coordinates between the base, and the other vertex, so \"height+=4-2=2\" .
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\n" ); document.write( "2) Would your teacher insist that you verify the coordinates with some calculations?
\n" ); document.write( "Maybe we should really verify that the lines intersect at points with exactly those coordinates,
\n" ); document.write( "by substituting those coordinates into the equations of the lines,
\n" ); document.write( "because sometimes things are not quite exactly the way they look.
\n" ); document.write( "We do not need to verify (0,2) ,
\n" ); document.write( "which we have shown above that is a point that
\n" ); document.write( "is part of blue line \"blue%28y=2%29\" , and
\n" ); document.write( "is part of red line \"red%282x-3y=-6%29\" .
\n" ); document.write( "Substituting \"system%28x=3%2Cy=4%29\" , the coordinates of (3,4),
\n" ); document.write( "we see that it is indeed a solution of \"system%28red%282x-3y=-6%29%2Cgreen%282x%2B3y-18=0%29%29\" .
\n" ); document.write( "Substituting \"system%28x=6%2Cy=2%29\" , the coordinates of (6,2),
\n" ); document.write( "we see that it is indeed a solution of \"system%28blue%28y=2%29%2Cgreen%282x%2B3y-18=0%29%29\" .
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