document.write( "Question 1099279: I have a problem:\"ln%28x%29=5163\". I got the correct answer on a problem similar to this: \"ln%28x%29=-4.16\". My process for the latter problem was to rewrite it as \"e%5E-4.16=x\"and then simplified it to \"1.56x10%5E-2=x\". My answer book indicated that answer as correct. When I tried to apply the same formula to the former problem, the calculator put up a notification saying ERROR. What was I doing wrong? Do I have the wrong formula and just got the second problem right by accident? I am using a CASIO fx-9750GII. Thanks for taking the time to help! \n" ); document.write( "
Algebra.Com's Answer #713713 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "You got the error message because no calculator can handle\r\n" );
document.write( "numbers as large as e5163.\r\n" );
document.write( "\r\n" );
document.write( "However, you can write numbers too large for the calculator\r\n" );
document.write( "in scientific notation.  Here's how to write e5163 in \r\n" );
document.write( "scientific notation:\r\n" );
document.write( "\r\n" );
document.write( "\"e%5E5163\"\"%22%22=%22%22\"\"10%5Ek\"\r\n" );
document.write( "\r\n" );
document.write( "Take natural logs of both sides\r\n" );
document.write( "\r\n" );
document.write( "\"5163\"\"%22%22=%22%22\"\"ln%2810%5Ek%29\"\r\n" );
document.write( "\r\n" );
document.write( "\"5163\"\"%22%22=%22%22\"\"k%2Aln%2810%29\"\r\n" );
document.write( "\r\n" );
document.write( "\"5163%2Fln%2810%29\"\"%22%22=%22%22\"\"k\"\r\n" );
document.write( "\r\n" );
document.write( "\"2242.26241\"\"%22%22=%22%22\"\"k\"\r\n" );
document.write( "\r\n" );
document.write( "Substitute in original equation above:\r\n" );
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document.write( "\"e%5E5163\"\"%22%22=%22%22\"\"10%5E2242.26241\"\"%22%22=%22%22\"\"10%5E2242%2A10%5E0.26241\"\"%22%22=%22%22\"\"10%5E2242%2A1.829827\"\"%22%22=%22%22\"\"1.829827%2A10%5E2242\"\r\n" );
document.write( "\r\n" );
document.write( "Edwin
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