document.write( "Question 1099275: A rock is thrown upward with a velocity of 25 meters per second from the top of a 20 meter high cliff, and it misses the cliff on the way back down. When will the rock be 7 meters from the water, below? Round your answer to two decimal places \n" ); document.write( "
Algebra.Com's Answer #713706 by Boreal(15235)\"\" \"About 
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the equation is h(t)=-4.9t^2+25t+20
\n" ); document.write( "That equals 7 when the rock is 7 meters above the water.
\n" ); document.write( "Therefore -4.9t^2+25t+13=0=4.9 t^2-25t-13
\n" ); document.write( "t=(1/9.8)(25+/- sqrt (625+254.8); sqrt term is 29.66
\n" ); document.write( "t=54.66/9.8=5.58 sec.
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