document.write( "Question 1099265: Find a polynomial with integer coefficients that satisfies the given conditions:
\n" ); document.write( "P has a degree 2 and zeros \"1%2Bi+sqrt%28+7+%29+\" and \"1-i+sqrt%28+7+%29+\"\r
\n" ); document.write( "\n" ); document.write( "I tried multiple times to get the formulat right, Im sorry I cant figure it out.
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Algebra.Com's Answer #713698 by Boreal(15235)\"\" \"About 
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Ax^2+Bx+C=0
\n" ); document.write( "the roots are 1+/- i sqrt(7)
\n" ); document.write( "in the quadratic formula, one divides by 2a, so let a=1 and we will be dividing by 2
\n" ); document.write( "if we do that, the numerator must be 2+/-2i sqrt(7)
\n" ); document.write( "this is 2+/- 2sqrt (-7); note that the sqrt term is sqrt (-28), because that may be broken down into sqrt(4)*sqrt(-7) which is 2*i sqrt(7)
\n" ); document.write( "b=-2
\n" ); document.write( "b^2-4ac=-28, a=1, b=-2, so find c
\n" ); document.write( "4-4(1)(c)=-28
\n" ); document.write( "-4c=-32
\n" ); document.write( "c=8
\n" ); document.write( "x^2-2x+8
\n" ); document.write( "\"graph%28300%2C300%2C-10%2C10%2C-10%2C20%2Cx%5E2%2B2x%2B8%29\"
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