document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1099231>Question 1099231</A>: <I><SPAN STYLE=\"word-break: break-all;\">  logb(x-1) + logb3 = logbx\r<BR>\n" );
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document.write( "I thought answer was -1.5 , that seems to be wrong.<BR>\n" );
document.write( "First I applied the product rule, so<BR>\n" );
document.write( "log_b(x+1) x log_b(3) = log_b(x)<BR>\n" );
document.write( "log_b(3x+3) =lob_b(X)<BR>\n" );
document.write( "log_b(3x+3)-log_b(x)=0<BR>\n" );
document.write( "Raise all the terms to power of log b<BR>\n" );
document.write( "3x+3-x=0<BR>\n" );
document.write( "2x+3=0<BR>\n" );
document.write( "2x=-3<BR>\n" );
document.write( "x=-3/2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #713668 by </B><A HREF=/tutors/aboutme.mpl?userid=Fombitz><B>Fombitz(32388)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Fombitz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Fombitz><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=713668\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First line of your solution should be,<BR>\n" );
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