document.write( "Question 1099231: logb(x-1) + logb3 = logbx\r
\n" ); document.write( "\n" ); document.write( "I thought answer was -1.5 , that seems to be wrong.
\n" ); document.write( "First I applied the product rule, so
\n" ); document.write( "log_b(x+1) x log_b(3) = log_b(x)
\n" ); document.write( "log_b(3x+3) =lob_b(X)
\n" ); document.write( "log_b(3x+3)-log_b(x)=0
\n" ); document.write( "Raise all the terms to power of log b
\n" ); document.write( "3x+3-x=0
\n" ); document.write( "2x+3=0
\n" ); document.write( "2x=-3
\n" ); document.write( "x=-3/2
\n" ); document.write( "

Algebra.Com's Answer #713667 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
logb(x-1) + logb3 = logbx\r
\n" ); document.write( "\n" ); document.write( "I thought answer was -1.5 , that seems to be wrong.
\n" ); document.write( "First I applied the product rule, so
\n" ); document.write( "log_b(x+1) x log_b(3) = log_b(x)
\n" ); document.write( "log_b(3x+3) =lob_b(X)
\n" ); document.write( "log_b(3x+3)-log_b(x)=0
\n" ); document.write( "Raise all the terms to power of log b
\n" ); document.write( "3x+3-x=0
\n" ); document.write( "2x+3=0
\n" ); document.write( "2x=-3
\n" ); document.write( "x=-3/2
\n" ); document.write( "=================
\n" ); document.write( "Your method and calculations are correct, but that gives
\n" ); document.write( "log(-5/2) + log(3) = log(-3/2)
\n" ); document.write( "Logs of negative numbers are not allowed.
\n" ); document.write( "--> no solution
\n" ); document.write( "
\n" );