document.write( "Question 1099203: If the length and width of a rectangle is increased by 1meter then the area of a rectangle is increased by 21meter^2 and if the length and width of a rectangle is decreased by 1mater then we area of a rectangle is decreased by 5meter^2.what is the perimeter of a rectangle?
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Algebra.Com's Answer #713633 by ankor@dixie-net.com(22740)\"\" \"About 
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Write an equation for each statement
\n" ); document.write( "If the length and width of a rectangle is increased by 1meter then the area of a rectangle is increased by 21meter^2
\n" ); document.write( "(L+1)*(w+1) = Lw + 21
\n" ); document.write( "FOIL
\n" ); document.write( "Lw + L + w + 1 = Lw + 21
\n" ); document.write( "combine like terms
\n" ); document.write( "Lw - Lw + L + w = 21 - 1
\n" ); document.write( "L + w = 20
\n" ); document.write( "Therefore
\n" ); document.write( "2L + 2W = 40 cm is the perimeter of rectangle 1
\n" ); document.write( "the original rectangle: 10 by 10 which is 100 sq/cm
\n" ); document.write( "the increased by 1 cm rectangle 11 by 11 which is 121 sq/cm
\n" ); document.write( ":
\n" ); document.write( "These are two different rectangles
\n" ); document.write( ":
\n" ); document.write( " and if the length and width of a rectangle is decreased by 1 meter then we area of a rectangle is decreased by 5meter^2.
\n" ); document.write( "(L-1)*(w-1) = Lw - 5
\n" ); document.write( "Lw - L - w + 1 = Lw - 5
\n" ); document.write( "Lw - Lw - L - w = - 5 - 1
\n" ); document.write( "-L - w = -6
\n" ); document.write( "multiply by -1
\n" ); document.write( "L + w = 6
\n" ); document.write( "therefore
\n" ); document.write( "2L + 2w = 12 cm is the perimeter of rectangle 2
\n" ); document.write( "Original rectangle 4 by 2 which is 8 sq cm
\n" ); document.write( "area of one decreased by 1: 3 by 1 = 3 sq/cm\r
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