document.write( "Question 1099048: An actor invests some money at 5%, and $22000 more than twice the amount at 11%. The total annual interest earned from the investment is $17540. How much did he invest at each amount? Use the six-step method. \n" ); document.write( "

Algebra.Com's Answer #713622 by jorel1380(3719) $\"\"$ $\"About$

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Let n and 2n+22,000 be the amounts invested at 5% and 11%, respectively. Then:
\n" ); document.write( ".05n+.11(2n+22,000)=17540
\n" ); document.write( ".05n+.22n+2420=17540
\n" ); document.write( ".27n=15120
\n" ); document.write( "n=56000
\n" ); document.write( "$56,000 was invested at 5%, and $134,000 was invested at 11%
\n" ); document.write( "☺☺☺☺ \n" ); document.write( "

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