document.write( "Question 1099172: Consider the following problem. Mike and Tim are looking to earn a little extra money. The beach committee offers them the opportunity off picking up plastic bottles, paying them $0.20 per bottle. Mike realizes as they pick up it will get harder and harder to find more bottles. So as an incentive to keep looking he suggest a different form of payment. He suggests $0.10 for the first bottle, and increase the pay by 2% for each bottle after that. Tim thinks Mike is crazy to propose an increase of just 2% per piece. He plans to ask for a one-cent increase for every piece, starting at 15 cents for the first bottle. Suppose the committee accepts each offer.
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document.write( "Answer the following in detail:
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document.write( "For Mike and Tim, write the first 5 terms of a sequence for payment scheme for each piece of paper.
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document.write( "Write a function to generate the n-th sequence values (bottle payment) for each Mike and Tim. Explain why you chose that function.
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document.write( "Using the formula how much will each receive for the 50th bottle? For the 100th bottle?
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document.write( "Determine the type of sequences for both Mike and Tim.
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document.write( "Who do you think fairs better in the long term? Explain \n" );
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Algebra.Com's Answer #713619 by jorel1380(3719) You can put this solution on YOUR website! Let n be the number of bottles each picks up. Then: \n" ); document.write( "Mike's bottles: .1 + 0.1*(1.02)^(n-1) represents the total pay for n bottles he picks up (for n>1) \n" ); document.write( "Tim's bottles: (0.15+.01(n-1)) for n bottles that Tim picks up \n" ); document.write( "For Mike, the 50th bottle equals: .1+0.1*(1.02)^49=.1+.26=0.36 \n" ); document.write( "For Tim, the 50th bottle is worth: .15+(.01)49=0.64 \n" ); document.write( "For Mike, the term is geometric, because the price per bottle rises exponentially, while for Tim the price per bottle rises algebraically, by a constan)t 1 cent per extra bottle. In the long run, Mike is going to make more per bottle. \n" ); document.write( "☺☺☺☺ \n" ); document.write( " |