document.write( "Question 1099107: derive the equation of a circle which passes through the point(-2,1), its tangent to the line 3x-2y-6=0 at the point (4,3) \n" ); document.write( "
Algebra.Com's Answer #713585 by Edwin McCravy(20083)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Here's a better way.\r\n" );
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document.write( "We set the lengths of the two green radii equal:\r\n" );
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document.write( "\"sqrt%28%28h-4%5E%22%22%29%5E2%2B%28k-3%5E%22%22%29%5E2%29\"\"%22%22=%22%22\"\"sqrt%28%28h-%28-2%29%5E%22%22%29%5E2%2B%28k-1%5E%22%22%29%5E2%29\"\r\n" );
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document.write( "That simplifies to:\r\n" );
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document.write( "\"3h%2Bk\"\"%22%22=%22%22\"\"5\"\r\n" );
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document.write( "That's one equation in h and k.\r\n" );
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document.write( "To get the other equation in h and k, we use the fact that a \r\n" );
document.write( "tangent to a circle is perpendicular to the radius drawn to the \r\n" );
document.write( "point of tangency.\r\n" );
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document.write( "We find the slope of the tangent line:\r\n" );
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document.write( "\"3x-2y-6\"\"%22%22=%22%22\"\"0\"\r\n" );
document.write( "\"-2y\"\"%22%22=%22%22\"\"-3x%2B6\"\r\n" );
document.write( "\"%28-2y%29%2F%28-2%29\"\"%22%22=%22%22\"\"expr%28%28-3%29%2F%28-2%29%29x%2B6%2F%28-2%29\"\r\n" );
document.write( "\"y\"\"%22%22=%22%22\"\"expr%283%2F2%29x-3\"\r\n" );
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document.write( "Comparing that to y = mx+b, the tangent line has slope\r\n" );
document.write( "\"3%2F2\" so the radius drawn to the point of tangency\r\n" );
document.write( "has slope \"-2%2F3\", its \"negative reciprocal\".\r\n" );
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document.write( "So we use the slope formula and set its slope equal to \"-2%2F3\"\r\n" );
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document.write( "\"%28k-3%29%2F%28h-4%29\"\"%22%22=%22%22\"\"-2%2F3\"\r\n" );
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document.write( "That simplifies to:\r\n" );
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document.write( "\"2h%2B3k\"\"%22%22=%22%22\"\"17\"\r\n" );
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document.write( "So we solve this system:\r\n" );
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document.write( "\"system%283h%2Bk=5%2C2h%2B3k=17%29\"\r\n" );
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document.write( "Solve that by substitution or elimination and get\r\n" );
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document.write( "\"%28matrix%281%2C3%2Ch%2C%22%2C%22%2Ck%29%29\"\"%22%22=%22%22\"\"%28matrix%281%2C3%2C-2%2F7%2C%22%2C%22%2C41%2F7%29%29\"\r\n" );
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document.write( "Then we find the length of the radius, using the distance\r\n" );
document.write( "formula for the length of the radius drawn to the point \r\n" );
document.write( "of tangency:\r\n" );
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document.write( "\"sqrt%28%28h-4%5E%22%22%29%5E2%2B%28k-3%5E%22%22%29%5E2%29\"\r\n" );
document.write( "\"sqrt%28%28-2%2F7-4%5E%22%22%29%5E2%2B%2841%2F7-3%5E%22%22%29%5E2%29\"\r\n" );
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document.write( "which simplifies to \"10sqrt%2813%29%2F7\"\r\n" );
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document.write( "Substituting for the center and radius in\r\n" );
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document.write( "\"%28x-h%29%5E2%2B%28y-k%29%5E2\"\"%22%22=%22%22\"\"r%5E2\"\r\n" );
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document.write( "\"%2810sqrt%2813%29%2F7%29%5E2\"\r\n" );
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document.write( "which simplifies to:\r\n" );
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document.write( "\"%28x+%2B+2%2F7%29%5E2+%2B+%28y+-+41%2F7%29%5E2\"\"%22%22=%22%22\"\"1300%2F49\"\r\n" );
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document.write( "Edwin
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