document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1099147>Question 1099147</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose that a constant force is applied to an object. Newton's Second Law of Motion states that the acceleration of the object varies inversely with its mass. A certain force acting upon an object with mass <BR>\n" );
document.write( "6 kg\r<BR>\n" );
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document.write( " produces an acceleration of <BR>\n" );
document.write( "5 /ms2\r<BR>\n" );
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document.write( ". If the same force acts upon another object whose mass is <BR>\n" );
document.write( "10 kg\r<BR>\n" );
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document.write( ", what would this object's acceleration be?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #713542 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=713542\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a=k/m, units are ms^-2=k/kg so k is kg-m/sec^2<BR>\n" );
document.write( "find k<BR>\n" );
document.write( "5=k/6<BR>\n" );
document.write( "k=30<BR>\n" );
document.write( "use k in the next part<BR>\n" );
document.write( "a=30/10=3 m/sec^2 </SPAN>\n" );
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