document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1099107>Question 1099107</A>: <I><SPAN STYLE=\"word-break: break-all;\"> derive the equation of a circle which passes through the point(-2,1), its tangent to the line 3x-2y-6=0 at the point (4,3) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #713520 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=713520\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> derive the equation of a circle which passes through the point A(-2,1), its tangent to the line 3x-2y-6=0 at the point B(4,3)<BR>\n" );
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document.write( "Step 1, find the equation of the line perpendicular to the given line thru the point (4,3) --- point B<BR>\n" );
document.write( "The center is on that line.<BR>\n" );
document.write( "Step 2, find the perpendicular bisector of AB.<BR>\n" );
document.write( "The center is on that line, too.<BR>\n" );
document.write( "The center is the intersection of the 2 lines.<BR>\n" );
document.write( "r is the distance from the center to either point.<BR>\n" );
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