document.write( "Question 1099109: Alvin paddled for 5 hours with a 3-km/h current to reach a campsite. The return trip against the same current took 8 hours.\r
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document.write( "What is the speed of the boat in still water?
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Algebra.Com's Answer #713510 by Theo(13342)![]() ![]() You can put this solution on YOUR website! rate * time = distance.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "let r = rate and t = time and d = distance\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "going downstream, the formula becomes (r+3) * 5 = d \n" ); document.write( "coming back upstream, the formula becomes (r-3) * 8 = d\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the distance downstream is the same as the distance upstream, so (r+3) * 5 = (r-3) * 8\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "simplify to get 5r + 15 = 8r - 24\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "subtract 5r from both sides of this equation and add 24 to both sides of this equation to get 39 = 3r\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for r to get r = 39/3 = 13\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "he paddles at 13 kilometers per hour.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "going downstream, the stream adds 3 kilometers per hours to this to get 16 kilometers per hour for 5 hours = 80 kilometers.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "coming back upstream, the stream subtracts 3 kilometers from this to get 10 kilometers per hour for 8 hours = 80 kilometers.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the distance downstream and upstream is the same at 80 kilometers.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the speed of the boat is 13 kilometers per hour \n" ); document.write( " |