document.write( "Question 1099112: On a weekend​ outing, Carlos rents a motorboat for 10 hours to travel down the river and back. The rental operator tells him to go for 4 hours​ downstream, leaving 6 hours to return upstream.\r
\n" ); document.write( "\n" ); document.write( "If the river current flows at a speed of 5 mph, how fast must Carlos travel in order to return in 10 hours?
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Algebra.Com's Answer #713509 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
rate * time = distance.\r
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\n" ); document.write( "\n" ); document.write( "let r = rate
\n" ); document.write( "time is in hours
\n" ); document.write( "distance is in miles\r
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\n" ); document.write( "\n" ); document.write( "going downstream, the formula becomes (r+5)*4 = distance downstream
\n" ); document.write( "going upstream, the formula becomes (r-5) * 6 = distance upstream\r
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\n" ); document.write( "\n" ); document.write( "the distance downstream is the same as the distance upstream.\r
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\n" ); document.write( "\n" ); document.write( "therefore (r+5)*4 = (r-5)*6
\n" ); document.write( "simplify to get 4r+20 = 6r-30
\n" ); document.write( "subtract 4r from both sides of this equation and add 30 to both sides of this equation to get 50 = 2r
\n" ); document.write( "solve for r to get r = 25.\r
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\n" ); document.write( "\n" ); document.write( "his boat needs to travel at 25 miles per hour.\r
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\n" ); document.write( "\n" ); document.write( "going downstream, the stream adds 5 miles per hour to that for a total of 30 miles per hour for 4 hours to equal a distance of 120 miles.\r
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\n" ); document.write( "\n" ); document.write( "coming back upstream, the stream subtracts 5 miles per hour from that for a total of 20 miles per hour for 6 hours to equal a total distance of 120 miles.\r
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\n" ); document.write( "\n" ); document.write( "carlos needs to travel 25 miles per hour to go downstream and come back upstream in 10 hours.\r
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\n" ); document.write( "\n" ); document.write( "that's what i get.\r
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