document.write( "Question 1098992: Log3(x+1)=log3(x-1)+1 \n" ); document.write( "
Algebra.Com's Answer #713435 by Alan3354(69443)\"\" \"About 
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Log3(x+1)=log3(x-1)+1
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\n" ); document.write( "\"log%283%2C%28x%2B1%29%29+=+log%283%2C%28x-1%29%29+%2B+log%283%2C3%29\"
\n" ); document.write( "\"log%283%2C%28x%2B1%29%29+=+log%283%2C%283%28x-1%29%29%29\"
\n" ); document.write( "x+1 = 3(x-1) = 3x-3
\n" ); document.write( "2x = 4
\n" ); document.write( "x = 2\r
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