document.write( "Question 1098992: Log3(x+1)=log3(x-1)+1 \n" ); document.write( "

Algebra.Com's Answer #713403 by ikleyn(52788) $\"\"$ $\"About$

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\n" ); document.write( "Log3(x+1)=log3(x-1)+1
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document.write( " =  + 1  ====>\r\n" );
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document.write( "x + 1 = 3*(x-1)  ====>  x+1 = 3x - 3  ====>  1+3 = 2x  ====>  x =  = 2.\r\n" );
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document.write( "Answer.  x = 2.\r\n" );
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