document.write( "Question 1098969: Two airplane (a passenger plane and a cargo plane) leave Abbotsford airport at the same time. The passenger plane travels at a bearing of 15 degree and a speed of 720 kph. The cargo jet travel at a bearing of 95 degree and a speed of 650 kph. How far apart will they be after 3 hours? \n" ); document.write( "
Algebra.Com's Answer #713387 by Fombitz(32388)\"\" \"About 
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Rate x Time = Distance
\n" ); document.write( "Break down the distance into x and y components.
\n" ); document.write( "The first plane travels from the airport at (\"0\",\"0\") to
\n" ); document.write( "(\"3%2A720cos%28115%29\",\"3%2A720sin%28115%29\")=(\"-912\",\"1958\")
\n" ); document.write( "The second plane travels from the airport to
\n" ); document.write( "(\"3%2A650%2Acos%2895%29\",\"3%2A650%2Asin%2895%29\")= (\"-170\",\"1942\")
\n" ); document.write( "Now use the distance formula,
\n" ); document.write( "\"D%5E2=%28-912-%28-170%29%29%5E2%2B%281958-1942%29%5E2\"
\n" ); document.write( "\"D=sqrt%28550564%2B+256%29\"
\n" ); document.write( "Work that out to get the distance in km.
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