document.write( "Question 1098822: Hi
\n" ); document.write( "there were 900 sweets in boxes a b c.18 sweets were transfered from a to b.5 sweets were transferred from b to c.1/3 of the sweets in c were then transferred to a.there were an equal number of sweets in all 3 boxes. How many sweets were in each box at first.\r
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Algebra.Com's Answer #713245 by ikleyn(52782) $\"\"$ $\"About$

You can put this solution on YOUR website!
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document.write( "The condition says that after all exchanges there were an equal number of sweets in all 3 boxes.\r\n" );
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document.write( " = 300, which means that finally there were 300 sweets in each box.\r\n" );
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document.write( "Further, the condition says\r\n" );
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document.write( "a - 18 +  = 300,    (1)\r\n" );
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document.write( "b + 18 - 5 = 300,           (2)\r\n" );
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document.write( "(c+5) -  = 300.     (3)\r\n" );
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document.write( "From (3),   = 300  ====>  c+5 =  =  = 450  ====>  c = 450-5 = 445.\r\n" );
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document.write( "From (2),  b = 300 + 5 - 18 = 287.\r\n" );
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document.write( "From (1), a = 300 -  + 18 = 300 - 150 + 18 = 168.\r\n" );
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document.write( "Answer.  Originally, there were 168 sweets in A, 287 sweets in B  and 445 sweets in C.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Solved.\r
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\n" ); document.write( "\n" ); document.write( "      There is NO NEED to solve system in 3 equations in 3 unknowns.\r
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\n" ); document.write( "\n" ); document.write( "      This problem is for young students (5 - 6 grades) who have no any notion on systems of equations.\r
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\n" ); document.write( "\n" ); document.write( "      The solution and the approach by @josgarithmetic go entirely and totally out of the target.\r
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\n" ); document.write( "\n" ); document.write( "      For your safety, simply ignore his writing.\r
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