document.write( "Question 1098832: Five years ago, Ked was three time as old as Doy. Five years hence, Ked will be twice as old as Doy. Find their present ages.
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Algebra.Com's Answer #713231 by Fombitz(32388)\"\" \"About 
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Five years ago,
\n" ); document.write( "\"K-5=3%28D-5%29\"
\n" ); document.write( "\"K-5=3D-15\"
\n" ); document.write( "1.\"K-3D=-10\"
\n" ); document.write( "Five years from now,
\n" ); document.write( "\"K%2B5=2%28D%2B5%29\"
\n" ); document.write( "\"K%2B5=2D%2B10\"
\n" ); document.write( "2.\"K-2D=5\"
\n" ); document.write( "Subtract 2 from 1,
\n" ); document.write( "\"K-3D-K%2B2D=-10-5\"
\n" ); document.write( "\"-D=-15\"
\n" ); document.write( "\"D=15\"
\n" ); document.write( "Now use either equation to solve for K.\r
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