document.write( "Question 97985This question is from textbook
\n" ); document.write( ": In a bicycle race, Lionel gives Robert a 500m advantage. Also, Lionel agrees to start 15min after Robert. If Lionel bikes at 17km/h and Robert at 14km/h, how long will it take Lionel after he starts biking to overtake Robert?\r
\n" ); document.write( "\n" ); document.write( "I already know that you have to convert 500m to 0.5km and 15min to 0.25hours. I have to make an equation out of this but I don't know how. Please help. \n" ); document.write( "
Algebra.Com's Answer #71322 by ankor@dixie-net.com(22740)\"\" \"About 
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In a bicycle race, Lionel gives Robert a 500m advantage. Also, Lionel agrees to start 15min after Robert. If Lionel bikes at 17km/h and Robert at 14km/h, how long will it take Lionel after he starts biking to overtake Robert?
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\n" ); document.write( "When L overtakes R, L will have traveled .5 km further than
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\n" ); document.write( "Let t = travel time for L to overtake R
\n" ); document.write( "Then
\n" ); document.write( "(t+.25) = travel time of R (had a 15 min head start)
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\n" ); document.write( "Distance = speed * time
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\n" ); document.write( "L's distance = R's distance + .5 (R had a 500 m head start)
\n" ); document.write( "17t = 14(t+.25) + .5
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\n" ); document.write( "17t = 14t + 3.5 + .5
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\n" ); document.write( "17t - 14t = 4
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\n" ); document.write( "3t = 4
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\n" ); document.write( "t = 4/3 hr for L to overtake R
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\n" ); document.write( "Check the distance of both:
\n" ); document.write( "17*(4/3) = 22.68 mi
\n" ); document.write( "14*(4/3 + 1/4) = 22.17, .5 mi difference because of the head start \n" ); document.write( "
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