document.write( "Question 1098385: a. How many ways are there to choose four fives from a standard 52-card deck?
\n" ); document.write( "b. How many ways are there to choose one card from a standard 52-card deck without choosing any fives?
\n" ); document.write( "c. How many five-card hands (drawn from a standard 52-card deck) contain exactly four fives?
\n" ); document.write( "d. How many five-card hands (drawn from a standard 52-card deck) contain a four-of-a-kind?
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Algebra.Com's Answer #713202 by KMST(5328)\"\" \"About 
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a. How many ways are there to choose four fives from a standard 52-card deck?
\n" ); document.write( "There are only 4 fives, so there is only 1 possible set of fives you can get..
\n" ); document.write( "There is only 1 such combination, and that is what I believe was meant by the question.
\n" ); document.write( "(If you cared what order the cards were received, there would be 4!=4*3*2=24 permutataions).
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\n" ); document.write( "b. How many ways are there to choose one card from a standard 52-card deck without choosing any fives?
\n" ); document.write( "52-4=48 of the cards are not a five,
\n" ); document.write( "so there are 48 ways to choose one card from a standard 52-card deck without choosing any five.
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\n" ); document.write( "c. How many five-card hands (drawn from a standard 52-card deck) contain exactly four fives?
\n" ); document.write( "As there is exactly 1 set of 4 fives, and 48 ways to choose the 5th card,
\n" ); document.write( "there are 1 X 48 = 48 five-card hands containing exactly four fives.
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\n" ); document.write( "d. How many five-card hands (drawn from a standard 52-card deck) contain a four-of-a-kind?
\n" ); document.write( "There are 52/4=13 different \"kinds of cards in a standard 52-card deck.
\n" ); document.write( "There are 48 five-card hands containing exactly four fives.
\n" ); document.write( "There are also
\n" ); document.write( "48 five-card hands containing exactly four aces,
\n" ); document.write( "48 five-card hands containing exactly four twos,
\n" ); document.write( "48 five-card hands containing exactly four threes,
\n" ); document.write( "48 five-card hands containing exactly four fours,
\n" ); document.write( "48 five-card hands containing exactly four sixes,
\n" ); document.write( "and so on.
\n" ); document.write( "Considering all 13 kinds of cards there are 13 X 48 = 624
\n" ); document.write( "card hands containing four-of-a-kind.
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