Algebra.Com's Answer #713167 by ikleyn(52781)![\"\"](\"/images/stars/stars-13.gif\")  
You can put this solution on YOUR website!
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document.write( "Check your line 1. \r\n" );
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document.write( "I think that it must be \r\n" );
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document.write( " = 0. (In plain text format form it is 3*(3^(2x)) - 28*3^x + 9 = 0.)\r\n" );
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document.write( "If it is so, then it is a quadratic equation relative  .\r\n" );
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document.write( "For many solved problems of this type (your samples) see the lesson\r
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document.write( " - Solving exponential equations\r
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document.write( "Also, you have this free of charge online textbook in ALGEBRA-I in this site\r
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document.write( " - ALGEBRA-I - YOUR ONLINE TEXTBOOK.\r
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document.write( "The referred lesson is the part of this online textbook under the topic \"Exponential equations\".\r
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document.write( "Save the link to this online textbook together with its description\r
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document.write( "Free of charge online textbook in ALGEBRA-I
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document.write( "https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson\r
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document.write( "to your archive and use it when it is needed.\r
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document.write( "Comment from student: No. Equation is written as in the textbook. It is a lesson not on quadratic equations but on exponential equations. Thank you for the link.
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document.write( "My response. Below is the plot of the function in the lft side of your 1-st line.\r
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document.write( "Plot y = 3(3^2x) - 28(3^x) + 9 =  \r
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document.write( "There is NO ANY SENSE to argue with me.\r
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