document.write( "Question 1098764: The inequality 0<2x^2+bx+5 has an infinite number of real solutions when..
\n" ); document.write( "1) -2√10 < b < 2√10
\n" ); document.write( "2) b<-2√10 or b> 2√10
\n" ); document.write( "3) -2√10 ≤ b ≤ 2√10
\n" ); document.write( "4) b≤ -2√10 or b≤ 2√10\r
\n" ); document.write( "\n" ); document.write( "Would it work if I used the discriminant formula to solve this? And how would I solve it? I would greatly appreciate an answer!
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Algebra.Com's Answer #713144 by josgarithmetic(39631)\"\" \"About 
You can put this solution on YOUR website!
The quadratic function would be greater than zero for all x. This means the discriminant must be negative. That should help you.\r
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\n" ); document.write( "\n" ); document.write( "\"2x%5E2%2Bbx%2B5%3E0\"\r
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\n" ); document.write( "\n" ); document.write( "Discriminant is \"b%5E2-4%2A2%2A5\",
\n" ); document.write( "\"b%5E2-40\".\r
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\n" ); document.write( "\n" ); document.write( "The function \"2x%5E2%2Bbx%2B5\" is a parabola having a minimum vertex and the parabola opens upward. If \"b%5E2-40%3E0\", then the parabola will cross the x-axis in two places and there will be some points below the x-axis. If \"b%5E2-40%3C0\", then the parabola will not touch nor cross the x-axis anywhere, and all points of the parabola will be greater than 0 (or all points will be above the x-axis).
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