document.write( "Question 1098700: How many distinguishable course codes can be obtained by rearranging MAA2312? Note that the 3 letters must come first and then the 4 numbers.
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Algebra.Com's Answer #713112 by math_helper(2461) $\"\"$ $\"About$

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Ans: $\"+highlight%2836%29+\"$ different course codes
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\n" ); document.write( "Workout:
\n" ); document.write( "There are 3 unique arrangements of MAA (to see this, assume you had $\"+M+\"$ , $\"A%5B1%5D\"$ , and $\"A%5B2%5D+\"$ , there would be 3! = 6 ways to arrange those, but we need to divide by 2!, because $\"A%5B1%5D+\"$ and $\"A%5B2%5D+\"$ are really just \"A\" and therefore not distinguishable, so we need to divide that 6 by the number of arrangements of $\"+A%5B1%5D+\"$ and $\"+A%5B2%5D+\"$ : 6/2 = 3)
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\n" ); document.write( "There are 12 unique arrangements of 2,3,1,2 (4!/2! = 24/2 = 12)
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\n" ); document.write( "3*12 = 36
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