document.write( "Question 1098700: How many distinguishable course codes can be obtained by rearranging MAA2312? Note that the 3 letters must come first and then the 4 numbers.
\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #713109 by ikleyn(52781) $\"\"$ $\"About$

You can put this solution on YOUR website!
.
\n" ); document.write( "

\r\n" );
document.write( "Regarding first three letters, there are   = 3 distinguishable words/arrangements.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Regarding last four digits, there are  = 12 distinguishable arrangements.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "In all, 3*12 = 36 distinguishable course codes can be obtained.\r\n" );
document.write( "

\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );