document.write( "Question 1098670: a loan is repaid with equal payments of 200 dollar at the end of each week for 15 years .if interest is 10.4% p.a. compounded weekly and assuming that there are 52 weeks in a year,
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document.write( "(a) the total amount repaid,
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document.write( "(b) the present value of the loan (correct to 2 decimal places),
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document.write( "(c) the total amount of interest paid (correct to 2 decimal places).\r
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Algebra.Com's Answer #713058 by Theo(13342) You can put this solution on YOUR website! payments are 200 dollars at the end of each week for 15 years. \n" ); document.write( "interest rate is 10.4% per year compounded weekly. \n" ); document.write( "assuming 52 weeks in a year, you would translate this problem as follows for the online calculator at \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "present value = 0 \n" ); document.write( "future value = 0 \n" ); document.write( "number of periods = 15 * 52 = 780 weeks \n" ); document.write( "payment amount = -200 \n" ); document.write( "interest rate % per period = 10.4 / 52 = .2 \n" ); document.write( "payment made at end of time period\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you would then click on PV and the calculator will tell you that the present value of the loan is $78,953.63\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the total payments you made would be 780 * $200 = $156,000\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the total interest you paid would be $156,000 - $78,953.63 = $77,046.37\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the calculator i used is at https://arachnoid.com/finance/\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "here's a picture of the results from this calculator.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you could also have calculated manually using the following formula.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "PRESENT VALUE OF AN ANNUITY WITH END OF TIME PERIOD PAYMENTS \r \n" ); document.write( "\n" ); document.write( "p = (a*(1-1/(1+r)^n))/r \r \n" ); document.write( "\n" ); document.write( "p is the present value of the annuity. \n" ); document.write( "a is the annuity. \n" ); document.write( "r is the interest rate per time period. \n" ); document.write( "n is the number of time periods. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "in your problem:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a = 200 \n" ); document.write( "r = 10.4 / 100 = .104 / 52 = .002 \n" ); document.write( "n = 15 * 52 = 780\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the formula of p = (a*(1-1/(1+r)^n))/r becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "p = (200*(1-1/(1.002)^780))/.002\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the result would be p = $78,953.62978 which is equal to $78,953.63 rounded to 2 decimal places.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that's the same result that the calculator gave you.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a summary of financial formulas that you might find useful can be found at this link.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "https://www.algebra.com/algebra/homework/Finance/THEO-2016-04-29.lesson#f5 \n" ); document.write( " \n" ); document.write( " |