document.write( "Question 1098556: Two equal sized vats, A and B containing 1000L of oil, are slowly being drained. Given that each Vat is being drained at a constant rate and that it takes 4 hours to drain Vat A completely and 5 hours to drain Vat B completely, find the time at which the amount of oil in Vat B is four times the amount of oil in Vat A. \n" ); document.write( "
Algebra.Com's Answer #712950 by richwmiller(17219)\"\" \"About 
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1000/4=250 L/h
\n" ); document.write( "1000/5=200 L/h
\n" ); document.write( "4(1000 - 250t)=1000 - 200t
\n" ); document.write( "4000 - 1000t=1000 - 200t
\n" ); document.write( "800t=3000
\n" ); document.write( " t=3.75 hours
\n" ); document.write( "
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