document.write( "Question 1098549: An individual invested 50000rs in two types of bonds. He receives an interest from one at the rate 8% per annum and from the other at the rate of 12% per annum. If his annual income from these is 5000rs, how much money was invested in each bond? \n" ); document.write( "

Algebra.Com's Answer #712945 by ikleyn(52781) $\"\"$ $\"About$

You can put this solution on YOUR website!
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document.write( "Invested x at 8% and (50000-x) at 12%.\r\n" );
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document.write( "0.08x + 0.12*(50000-x) = 5000\r\n" );
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document.write( "0.08 + 0.12*50000 - 0.12x = 5000\r\n" );
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document.write( "-0.04x = 5000 - 0.12*50000 = -1000.\r\n" );
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document.write( "x =  = 25000.\r\n" );
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document.write( "Answer.  rs 25000 was invested at 8%  and  rs50000 - rs25000 = rs 25000 was invested at 12%.\r\n" );
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\n" ); document.write( "\n" ); document.write( "The solution by @josgarithmetic is WR O N G. \r
\n" ); document.write( "\n" ); document.write( "For your safety, simply ignore it.\r
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\n" ); document.write( "Since @josgarithmetic changed his post after my noticing,
\n" ); document.write( "below is what was written in the @josgarithmetic solution when I noticed his error (a copy)\r
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\n" ); document.write( "\n" ); document.write( "Invested x of rs at 8% and 50000-x at 12%\r
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\n" ); document.write( "\n" ); document.write( " $\"0.08x%2B0.12%2850000-x%29=5000\"$ \r
\n" ); document.write( "\n" ); document.write( "-\r
\n" ); document.write( "\n" ); document.write( " $\"0.08%2B0.12%2A50000-0.12x=5000\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"-0.04x=5000-0.12%2A50000\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x=2500\"$ -----------rs at 8%.\r
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