document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1098526>Question 1098526</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The height and base of a right angled triangle are 15cm and 20cm. If the height is increased by 60%, and the base reduced by 60%, what is the percent change in area? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #712938 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=712938\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br>Dear tutor MathTherapy:<br><BR>\n" );
document.write( "I don't get it.  Another tutor posts a perfectly good, although not very efficient, solution to the problem.  Then you provide an answer without showing any work at all, and you tell the reader to \"ignore the nonsense\" that the other tutor provided.<br><BR>\n" );
document.write( "So you think that an answer with no indication whatsoever of how to solve the problem is more useful to a student than a solution that maybe uses a method you personally don't like??!!<br><br><BR>\n" );
document.write( "To the reader....<br><BR>\n" );
document.write( "You don't need to do anything with the given measurements of the triangle.  All you need to know is that the formula for the area of the triangle is one-half base times height.<br><BR>\n" );
document.write( "Since the formula is that straightforward, all you need to use to get the answer is to know that the height was increased by 60% and the base was reduced by 60%.<br><BR>\n" );
document.write( "An increase of 60% means the height was multiplied by <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281%2B.60%29+=+1.60 ALIGN=MIDDLE  ALT=\"%281%2B.60%29+=+1.60\"   DISABLED_style= \"max-width:90%; height:auto;\" >; a decrease of 60% means the base was multiplied by <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281-.60%29+=+0.40 ALIGN=MIDDLE  ALT=\"%281-.60%29+=+0.40\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Then the area was multiplied by <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1.6%2A0.4+=+0.64 ALIGN=MIDDLE  ALT=\"1.6%2A0.4+=+0.64\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<br><BR>\n" );
document.write( "So the new area is 64% of what is was; that means the area was reduced by (100-64) = 36%.<br><BR>\n" );
document.write( "Note a quicker way to see the answer of a 36% reduction is to look at the multiplying factors this way: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281%2B.6%29%2A%281-.6%29+=+%281%29%5E2+-+%28.6%29%5E2+=+1-.36 ALIGN=MIDDLE  ALT=\"%281%2B.6%29%2A%281-.6%29+=+%281%29%5E2+-+%28.6%29%5E2+=+1-.36\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "When you do the calculation this way, you immediately see that the answer is a reduction of 36%. </SPAN>\n" );
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