document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1098484>Question 1098484</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3 clocks, hour hands are missing, have minute hands running fast.\r<BR>\n" );
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document.write( "Clock P, Q, R gain 2, 6, 12 mins per hour respectively.\r<BR>\n" );
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document.write( "They start at midday - pointing to 12.\r<BR>\n" );
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document.write( "Find the number of hours later when all 3 hands show the same number of minutes. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #712912 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=712912\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I came up with 30 hrs all three hands will be straight up at 12<BR>\n" );
document.write( "I reasoned thus<BR>\n" );
document.write( "P hand: After 30 hrs, it will be 30*2 = 60 min or exactly 1 hour<BR>\n" );
document.write( "Q hand: After 30 hrs, it will be 30*6 = 180 min or exactly 3 hrs ahead<BR>\n" );
document.write( "R hand: After 30 hrs, it will be 30*12 = 360 min or exactly 6 hrs ahead<BR>\n" );
document.write( ":<BR>\n" );
document.write( "I may be full of the well-known waste product here, but there it is.<BR>\n" );
document.write( "Let me know: ankor@att.net, I have made many mistakes in my life and am used to it.  </SPAN>\n" );
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