document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1098528>Question 1098528</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the P(1,4,1) on three consecutive rolls of a number cube? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #712909 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=712909\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> It is 1/216, because they are independent of each other, and the probability of any given number is 1/6.<BR>\n" );
document.write( "(1/6)^3=1/216<BR>\n" );
document.write( "If it were two 1s and 1 4, that would be different, for it could be 1,1,4 or 4,1,1. </SPAN>\n" );
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