document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1098533>Question 1098533</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If it take Karen 2 hours to wax SUV and Clarann 3 hours how long would it take them to wax it together.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #712908 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=712908\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> in 1 hour<BR>\n" );
document.write( "Karen does (1/2) and Clarann does (1/3)<BR>\n" );
document.write( "In x hours (x/2) and (x/3)<BR>\n" );
document.write( "Set those two, their sum, equal to 1<BR>\n" );
document.write( "(x/2)+(x/3)=1<BR>\n" );
document.write( "multiply everything by LCD of 6<BR>\n" );
document.write( "3x+2x=6<BR>\n" );
document.write( "5x=6<BR>\n" );
document.write( "x=6/5=1.2<BR>\n" );
document.write( "it would take them together 1.2 hours, for it would be 1.2/2 (60%) for K and 1.2/3 (40%) for C. </SPAN>\n" );
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