document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=125288>Question 125288</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many gallons of an 80% alcohol solution must be mixed with 30 gallons of a 22% solution to obtain a solution that is 70% alcohol? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #712904 by </B><A HREF=/tutors/aboutme.mpl?userid=amalm06><B>amalm06(224)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amalm06><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=amalm06><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=712904\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (x)(0.80)+(30)(0.22)=(30+x)(0.70)\r<BR>\n" );
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document.write( "0.8x+6.6=21+0.7x\r<BR>\n" );
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document.write( "0.1x=14.4\r<BR>\n" );
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document.write( "x=144 gallons (Answer)\r<BR>\n" );
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document.write( "Alternatively, we may use the method of alligation.\r<BR>\n" );
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document.write( "0.70-0.22=0.48\r<BR>\n" );
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document.write( "0.80-0.70=0.10\r<BR>\n" );
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document.write( "Then T1/T2=0.10/0.48=0.2083333\r<BR>\n" );
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document.write( "Since T1=30, we have 30/T2=0.2083333\r<BR>\n" );
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document.write( "T2=144 gallons (Answer)\r<BR>\n" );
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document.write( " </SPAN>\n" );
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