document.write( "Question 1098484: 3 clocks, hour hands are missing, have minute hands running fast.\r
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document.write( "Clock P, Q, R gain 2, 6, 12 mins per hour respectively.\r
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document.write( "They start at midday - pointing to 12.\r
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document.write( "Find the number of hours later when all 3 hands show the same number of minutes. \n" );
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Algebra.Com's Answer #712887 by ikleyn(52776)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "============== \n" ); document.write( "My previous solution was WRONG. So, I took it out.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Below find the correct solution // (I came to it after seeing the tutor's @ankor@dixie-net.com solution, which is absolutely correct). \n" ); document.write( "==============\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "1. The readings difference between clocks Q and P has the rate of 4 min per hour.\r\n" ); document.write( "\r\n" ); document.write( " It means that their readings will coincide every 15 hours, when their minute hands are at the same positions \"verically up\".\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " It happens every 15 hours, and there is no other time moments, when their positions coincide.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "2. The readings difference between clocks R and P has the rate of 10 min per hour.\r\n" ); document.write( "\r\n" ); document.write( " It means that their readings will coincide every 6 hours, when their minute hands are at the same positions \"verically up\".\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " It happens every 6 hours, and there is no other time moments, when their positions coincide.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "3. The readings difference between clocks Q and R has the rate of 6 min per hour.\r\n" ); document.write( "\r\n" ); document.write( " It means that their readings will coincide every 10 hours, when their minute hands are at the same positions \"verically up\".\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " It happens every 10 hours, and there is no other time moments, when their positions coincide.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "4. It implies that the next and closest time moment when the readings of all 3 clock coincide comes in LCM (15,6,10) which is 30 hours.\r\n" ); document.write( "\r\n" ); document.write( " LCM is \"Leatt Common Multiple).\r\n" ); document.write( "\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer. In 30 hours.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Again: the answer by the tutor @ankor@dixie-net.com solution is absolutely correct.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |