document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1098501>Question 1098501</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The population of a city t years from now is given by P=250,000e^0.04t,<BR>\n" );
document.write( "Find the rate of change of population with respect to time t three years from now. (Round  your answer to the nearest integer.)<BR>\n" );
document.write( "(b)What is the actual change in population in the 4th year. (Round your answer to the nearest integer.)<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #712869 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=712869\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> derivative of 250000e^0.04t=0.04(250000)*e^0.04t, evaluated at t=3<BR>\n" );
document.write( "e^0.12=1.128, and without rounding, multiply by 0.04*250000=11,274.96, or 11275 people per year.<BR>\n" );
document.write( "between 3 and 4 years, the change will be 250000(e^0.16-e^0.12)=11,503.50 or 11,504 people. </SPAN>\n" );
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