document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1098440>Question 1098440</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two six-sided dice are rolled. What is the probability that one of the dice shows a 5 or the dice sum to 3? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #712833 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=712833\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br>There are 6*6 = 36 possible outcomes.<br><BR>\n" );
document.write( "The first die can be a 5 and the second can be any number: 6 ways.<BR>\n" );
document.write( "The second die can be a 5 and the first can be any number: 6 ways, for a total of 12.<BR>\n" );
document.write( "But now you have counted the outcome that both dice show a 5 twice, so subtract one from the total, to get 11.<BR>\n" );
document.write( "And to get a sum of 3 there are 2 possibilities, bringing the total to 13.<br><BR>\n" );
document.write( "So the probability is 13/36. </SPAN>\n" );
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