document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1098356>Question 1098356</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The angle of elevation from buoys C and D to the top of a cliff AB is 40 degrees and 30 degrees respectively. If Ross swims from C to D with a constant speed of 1.5m/s and AC=100m, find the distance between the two buoys.\r<BR>\n" );
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document.write( "Any help is greatly appreciated! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #712727 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=712727\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the triangles formed are ABC and ABD.\r<BR>\n" );
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document.write( "angle ACB is equal to 40 degrees.\r<BR>\n" );
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document.write( "angle ADB is equal to 30 degrees.\r<BR>\n" );
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document.write( "tan(40) = opposite / adjacent = AB / AC.\r<BR>\n" );
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document.write( "since AC = 100, this becomes tan(40) = AB / 100\r<BR>\n" );
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document.write( "solve for AB to get AB = 100 * tan(40) = 83.90996312\r<BR>\n" );
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document.write( "tan(30) = opposite / adjacent = AB / AD.\r<BR>\n" );
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document.write( "since AB is equal to 83.90996312, this becomes tan(30) = 83.90996312 / AD.\r<BR>\n" );
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document.write( "solve for AD to get AD = 83.90996312 / tan(30) = 145.3363194\r<BR>\n" );
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document.write( "since AD = AC + CD, then you get 145.3363194 = 100 + CD.\r<BR>\n" );
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document.write( "solve for CD to get CD = 145.3363194 - 100 = 45.3363194.\r<BR>\n" );
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document.write( "CD is the distance between the two buoys.\r<BR>\n" );
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document.write( "not sure where the speed comes in.\r<BR>\n" );
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document.write( "if the distance from A to C is 100 meters and ross swims at 1.5 meters per second, then it takes him 100 / 1.5 = 66.6666667 seconds to swim from A to C.\r<BR>\n" );
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document.write( "if he continues to swim at the same rate, then it takes him 45.3363194 / 1.5 = 30.22421292 seconds to swim buoy C to buoy D.\r<BR>\n" );
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document.write( "the total time it takes is 145.3363194 / 1.5 = 96.89087959  seconds to swim from the bottom of the cliff to buoy D.\r<BR>\n" );
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document.write( "to me, the speed at which he swam was irrelevant to the problem since you didn't need it to find the distance between buoy C and C.\r<BR>\n" );
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document.write( "here's the diagram i drew of the problem.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" src = \"http://theo.x10hosting.com/2017/102010.jpg\" alt=\"$$$\" >\r<BR>\n" );
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