document.write( "Question 1098331: find the value of K
\n" ); document.write( "2x^2+kx-12 given factor of 2x-3
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Algebra.Com's Answer #712684 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
If one of the factors is 2x-3, then one of the zeros would be \"3%2F2\".\r
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\n" ); document.write( "\n" ); document.write( "\"2%283%2F2%29%5E2%2B%283%2F2%29k-12=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"9%2A2%2F%282%2A2%29%2B%283%2F2%29k-12=0\"\r
\n" ); document.write( "\n" ); document.write( "\"18%2F4%2B3k%2F2-12=0\"\r
\n" ); document.write( "\n" ); document.write( "\"18%2B3%2A4k%2F2-48=0\"\r
\n" ); document.write( "\n" ); document.write( "\"18%2B6k-48=0\"\r
\n" ); document.write( "\n" ); document.write( "\"3%2Bk-8=0\"\r
\n" ); document.write( "\n" ); document.write( "\"k=8-3\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28highlight%28k=5%29%29\"\r
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