document.write( "Question 1098319: Determine the zeros, the degree, and the leading coefficient to graph this function. \r
\n" ); document.write( "\n" ); document.write( "f(x) = (x2+2x)(x-3) \n" ); document.write( "
Algebra.Com's Answer #712674 by ankor@dixie-net.com(22740)\"\" \"About 
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Determine the zeros, the degree, and the leading coefficient to graph this function.
\n" ); document.write( " f(x) = (x^2 + 2x)(x - 3)
\n" ); document.write( "Find the 0's
\n" ); document.write( "x^2 + 3x = 0
\n" ); document.write( "Factor out x
\n" ); document.write( "x(x + 3) = 0
\n" ); document.write( "x = 0
\n" ); document.write( "and
\n" ); document.write( "x = -3
\n" ); document.write( "@nd factor
\n" ); document.write( "x = 3
\n" ); document.write( "The zeros -3, 0, 3
\n" ); document.write( "The degree is 3 and leading coefficient is 1 but you can confirm that:
\n" ); document.write( "FOIL
\n" ); document.write( "(x^2+3x)*(x-3) = x^3 - 3x^2 + 3x^2 - 9x = x^3 - 9x
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