document.write( "Question 97890: please help with this
\n" ); document.write( "1. solve for x in 6x+12(10-x)=84
\n" ); document.write( "2. solve for d in -1/5(10d-5)=9
\n" ); document.write( "3.write an algebraic expression
\n" ); document.write( "\"the product of a number and three is one half of five time the number decreased by one\"
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Algebra.Com's Answer #71265 by anjali_yamini(27)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( " 1) 6x +12(10-x) = 84\r
\n" ); document.write( "\n" ); document.write( " 6x + 120 - 12x = 84\r
\n" ); document.write( "\n" ); document.write( " -6x + 120 = 84\r
\n" ); document.write( "\n" ); document.write( " 120 - 84 = 6x\r
\n" ); document.write( "\n" ); document.write( " 36 = 6x\r
\n" ); document.write( "\n" ); document.write( " 6 = x\r
\n" ); document.write( "\n" ); document.write( "check :\r
\n" ); document.write( "\n" ); document.write( " (6*6) +12(10-6)\r
\n" ); document.write( "\n" ); document.write( " = 36 +12*4\r
\n" ); document.write( "\n" ); document.write( " = 36 +48\r
\n" ); document.write( "\n" ); document.write( " = 84\r
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\n" ); document.write( "\n" ); document.write( "2) -1/5(10d-5) = 9\r
\n" ); document.write( "\n" ); document.write( " -10d/5 +5/5 = 9\r
\n" ); document.write( "\n" ); document.write( " -2d +1 = 9\r
\n" ); document.write( "\n" ); document.write( " -2d = 9- 1 = 8\r
\n" ); document.write( "\n" ); document.write( " d = - (8/2)\r
\n" ); document.write( "\n" ); document.write( " d = -4\r
\n" ); document.write( "\n" ); document.write( "check :\r
\n" ); document.write( "\n" ); document.write( " -1/5(-40-5)\r
\n" ); document.write( "\n" ); document.write( " = 40/5 + 5/5 \r
\n" ); document.write( "\n" ); document.write( " = 8 +1\r
\n" ); document.write( "\n" ); document.write( " = 9\r
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\n" ); document.write( "\n" ); document.write( "3) let the number = n\r
\n" ); document.write( "\n" ); document.write( " so, 3 times the number = 3*n
\n" ); document.write( " = 3n\r
\n" ); document.write( "\n" ); document.write( " 5 times the number = 5*n = 5n\r
\n" ); document.write( "\n" ); document.write( " so, 5 times the number minus 1 = 5n - 1\r
\n" ); document.write( "\n" ); document.write( " s0, half of 5 times the number - 1 = (5n-1)/2\r
\n" ); document.write( "\n" ); document.write( " so, 3n = (5n-1)/2
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