document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1098232>Question 1098232</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you convert R=2/3logE-3 into exponential Form? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #712641 by </B><A HREF=/tutors/aboutme.mpl?userid=yazimyne><B>yazimyne(8)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=yazimyne><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=712641\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> R=(2/3)log(E)-3<BR>\n" );
document.write( "(2/3)log(E)=R+3<BR>\n" );
document.write( "log(E^(2/3))=R+3<BR>\n" );
document.write( "BASE IS 10<BR>\n" );
document.write( "log =exponent =R+3<BR>\n" );
document.write( "YOUR RESULT IS<BR>\n" );
document.write( "E^(2/3)<BR>\n" );
document.write( "................ANSWER IS<BR>\n" );
document.write( "E^(2/3)=10^(R+3)\r<BR>\n" );
document.write( "\n" );
document.write( "EXPONENTIAL EQUATION........<BR>\n" );
document.write( "10^(R+3)=E^(2/3) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );