document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1098222>Question 1098222</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is three more than twice the width the perimeter is 66 cm find the length </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #712596 by </B><A HREF=/tutors/aboutme.mpl?userid=wilft1><B>wilft1(217)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=wilft1><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=wilft1><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=712596\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> word problems, gotta love em'<BR>\n" );
document.write( "i'm brain farting on the exact formula, but I was able to do it by visualizing it into my head <BR>\n" );
document.write( "2x + 6 + 2(2x) = 66<BR>\n" );
document.write( "your length is two lengths (on both sides of the rectangle), so 2x, 3 cm longer than the width, there are 2 sides so it will be + 3, then twice the width of the perimeter, so 2(2x)<BR>\n" );
document.write( "do the math and x = 10<BR>\n" );
document.write( "your shorter sides are 10 cm each, so width is 20 total<BR>\n" );
document.write( "longer side is twice the width and 3 more, so 10 + 10 + 3 = 23\r<BR>\n" );
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document.write( "two sides for length = 46, two sides for width is 20, perimeter = 66\r<BR>\n" );
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document.write( "length is 23<BR>\n" );
document.write( "width is 10 </SPAN>\n" );
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