document.write( "Question 1098180: What is the length of the edge of a cube if after a slice 1cm thick is cut from one side, the volume remaining 294 cubic cm? \n" ); document.write( "
Algebra.Com's Answer #712591 by KMST(5328)\"\" \"About 
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THE CARPENTER (OR THE CONFIDENT FIFTH-GRADER) SOLUTION:
\n" ); document.write( "I know how to calculate the volume of any shoe-box-shaped item.
\n" ); document.write( "You just multiply width, length and height.
\n" ); document.write( "For a cube, width length and height are all the same edge length.
\n" ); document.write( "If the cube edge length was 10 cm,
\n" ); document.write( "the initial cube volume would be
\n" ); document.write( "(10 cm) X (10 cm) X (10 cm) = 1000 cubic cm.
\n" ); document.write( "The volume of the slice cut off would be
\n" ); document.write( "(10 cm) X (10 cm) X (1 cm) = 100 cubic cm.
\n" ); document.write( "So, the final volume would be 900 cubic cm.
\n" ); document.write( "That is more than the 249 cm in the question.
\n" ); document.write( "
\n" ); document.write( "I also know that the larger the original cube,
\n" ); document.write( "the larger the final volume,
\n" ); document.write( "and the larger the final volume required,
\n" ); document.write( "the larger the original cube needed.
\n" ); document.write( "
\n" ); document.write( "What I know tells mne that the original cube edge must be less than 10 cm long.
\n" ); document.write( "It also tells me that there is only one answer.
\n" ); document.write( "If I calculate using increasing whole number lengths,
\n" ); document.write( "the calculated volumes will keep increasing,
\n" ); document.write( "so I will get to the answer and 249 cubic cm at some point,
\n" ); document.write( "or the answer was not a whole number length, and I will go past the answer.\r
\n" ); document.write( "\n" ); document.write( "I can calculate what the volume would be for a few edge lengths to see if I get 249 cubic cm as the answer.\r
\n" ); document.write( "\n" ); document.write( "If that happens, I will have the answer.
\n" ); document.write( "If not,
\n" ); document.write( "I will get less than 249 cubic cm for some whole number edge length,
\n" ); document.write( "but more than 249 cubic cm for the next whole number edge length,
\n" ); document.write( "and I will know that the answer is somewhere in between.
\n" ); document.write( "
\n" ); document.write( "It is only common sense that the final volume is
\n" ); document.write( "more than the volume of a cube with edges 1 cm smaller.
\n" ); document.write( "I can easily calculate that a cube with edge length 5 cm has a volume of 125 cubic cm,
\n" ); document.write( "so the original cube's edge must be larger than 5 cm.\r
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\n" ); document.write( "THE HIGH-SCHOOLER SOLUTION:
\n" ); document.write( "If
\n" ); document.write( "\"x\"= length of the edge of the cube, in cm,
\n" ); document.write( "\"x%5E3\"= volume of the cube in cubic cm, and
\n" ); document.write( "\"x%2Ax%2A1=x%5E2\"= volume of a slice 1cm thick is cut from one side of the cube.
\n" ); document.write( "So, \"x%5E3-x%5E2=294\" is the volume remaining, in cubic cm.
\n" ); document.write( "
\n" ); document.write( "All you have to do is solve \"x%5E3-x%5E2=294\" <--> \"x%5E3-x%5E2-294=0\" for \"x\" .
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\n" ); document.write( "Solving:
\n" ); document.write( "\"x%5E3-x%5E2=294\"
\n" ); document.write( "\"%28x-1%29x%5E2=294\"
\n" ); document.write( "It so happens that
\n" ); document.write( "\"294=2%2A3%2A7%5E2=6%2A7%5E2\" , so \"x=7\" is a solution.
\n" ); document.write( "
\n" ); document.write( "Is that the only solution?
\n" ); document.write( "The way the problwm is worded,
\n" ); document.write( "you would think that there is only one solution,
\n" ); document.write( "so answering \"highlight%287cm%29\" ,
\n" ); document.write( "and going to the next problem would be a good strategy.
\n" ); document.write( "
\n" ); document.write( "With time and willingless to spare, you could dig deeper
\n" ); document.write( "using whatever tools you have.
\n" ); document.write( "
\n" ); document.write( "Using a graphing calculator, you could graph \"f%28x%29=x%5E3-x%5E2-294\" as
\n" ); document.write( "\"graph%28400%2C300%2C-7%2C9%2C-450%2C50%2Cx%5E3-x%5E2-294%29\" and find that \"x=7\" is the only solution.
\n" ); document.write( "
\n" ); document.write( "Using calculus:
\n" ); document.write( "\"f%28x%29=x%5E3-x%5E2-294\" could have 1 or 3 real zeros.
\n" ); document.write( "\"df%2Fdx=3x%5E2-2x=x%283x-2%29\" has zeros at \"x=0\" and \"x=2%2F3\" ,
\n" ); document.write( "representing respectively a local maximum and a local minimum for \"f%28x%29\" .
\n" ); document.write( "\"f%280%29=-294\" is the value of \"f%28x%29\" at its local maximum,
\n" ); document.write( "so \"f%28x%29+increases+for+%7B%7B%7Bx%3C0\" to local maximum \"f%280%29=-294\" ,
\n" ); document.write( "decreases at \"0%3Cx%3C2%2F3\" to a local minimum at \"x=2%2F3\" ,
\n" ); document.write( "and then increases for \"x%3E2%2F3\" .
\n" ); document.write( "So, there can be only one real zero for \"f%28x%29\" ,
\n" ); document.write( "it happens for some \"x%3E2%2F3\" ,
\n" ); document.write( "and as we already found that \"x=7\" is a zero, we know know that \"x=0\" is the only real zero for \"f%28x%29=x%5E3-x%5E2-294=0\".
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