document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1098184>Question 1098184</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Seven times a number if increased by 11 is 81 find the number? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #712586 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=712586\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x represent the number.\r<BR>\n" );
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document.write( "7x + 11 = 81<BR>\n" );
document.write( "subtract 11 from both sides of this equaton to get 7x + 11 = 11 = 81 - 11<BR>\n" );
document.write( "combine like terms to get 7x = 70<BR>\n" );
document.write( "divide both sides of this equation by 7 to get 7x/7 = 70/7<BR>\n" );
document.write( "simplify to get x = 10\r<BR>\n" );
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document.write( "10 is your number.\r<BR>\n" );
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document.write( "7 * 10 + 11 = 70 + 11 = 81\r<BR>\n" );
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