document.write( "Question 1098135: Richard is five years older than Sheila. Four times Sheila’s age increased by 3 years equals three time Richard’s age
\n" ); document.write( "diminished by 2 years. Find Richard’s age. \n" ); document.write( "

Algebra.Com's Answer #712563 by josmiceli(19441) $\"\"$ $\"About$

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(1) $\"+r+=+s+%2B+5+\"$
\n" ); document.write( "(2) $\"+4s+%2B+3+=+3r+-+2+\"$
\n" ); document.write( "----------------------
\n" ); document.write( "(2) $\"+3r+-+4s+=+5+\"$
\n" ); document.write( "and
\n" ); document.write( "(1) $\"+r+-+s+=+5+\"$
\n" ); document.write( "-----------------------
\n" ); document.write( "Multiply both sides of (1) by $\"+-4+\"$
\n" ); document.write( "(1) $\"+-4r+%2B+4s+=+-20+\"$
\n" ); document.write( "Add (1) and (2)
\n" ); document.write( "(1) $\"+-4r+%2B+4s+=+-20+\"$
\n" ); document.write( "(2) $\"+3r+-+4s+=+5+\"$
\n" ); document.write( "--------------------------
\n" ); document.write( " $\"+-r+=+-15+\"$
\n" ); document.write( " $\"+r+=+15+\"$
\n" ); document.write( "Richard is 15
\n" ); document.write( "----------------
\n" ); document.write( "check:
\n" ); document.write( "(1) $\"+r+-+s+=+5+\"$
\n" ); document.write( "(1) $\"+15+-+s+=+5+\"$
\n" ); document.write( "(1) $\"+s+=+10+\"$
\n" ); document.write( "and
\n" ); document.write( "(2) $\"+4s+%2B+3+=+3r+-+2+\"$
\n" ); document.write( "(2) $\"+4%2A10+%2B+3+=+3%2A15+-+2+\"$
\n" ); document.write( "(2) $\"+43+=+45+-+2+\"$
\n" ); document.write( "(2) $\"+43+=+43+\"$
\n" ); document.write( "OK
\n" ); document.write( " \n" ); document.write( "

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