document.write( "Question 1098146: It takes worker A six days longer as it takes worker B to finish a certain job. Working together, they finish the job in 4days. How many days will it take each to finish the job alone
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Algebra.Com's Answer #712557 by greenestamps(13200)\"\" \"About 
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Together they do the job in 4 days; so they do 1/4 of the job in 1 day.

\n" ); document.write( "Let x be the number of days worker A takes to do the job; then x+6 is the number of days worker B takes. Then 1/x is the fraction of the job worker A does in 1 day, and 1/(x+6) is the fraction worker B does in 1 day.

\n" ); document.write( "Now write the equation that says the amount they do together in 1 day is the sum of they each do alone in 1 day:

\n" ); document.write( "\"1%2F4+=+1%2Fx+%2B+1%2F%28x%2B6%29\"

\n" ); document.write( "Then solve the equation....
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