document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1098071>Question 1098071</A>: <I><SPAN STYLE=\"word-break: break-all;\"> This is factorization of polynomials, I just wanted to ask how this is factorized? Thank you.\r<BR>\n" );
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document.write( "(4+a)(4-a)-12-3a \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #712465 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=712465\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> start with (4+a) * (4-a) - 12 - 3a\r<BR>\n" );
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document.write( "(4+a) * (4-a) = 16 - a^2\r<BR>\n" );
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document.write( "expression becomes 16 - a^2 - 12 - 3a\r<BR>\n" );
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document.write( "rearrange in descending order of degree to get -a^2 - 3a - 12 + 16\r<BR>\n" );
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document.write( "combine like terms to get -a^2 - 3a + 4\r<BR>\n" );
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document.write( "set this equal to 0 to get -a^2 - 3a + 4 = 0\r<BR>\n" );
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document.write( "it's easier to factor if the coefficient of the x^2 term is positive so multiply both sides of the equation by -1 to get:\r<BR>\n" );
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document.write( "a^2 + 3a - 4 = 0\r<BR>\n" );
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document.write( "factor this quadratic equation to get (a+4) * (a-1) = 0\r<BR>\n" );
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document.write( "solve for a to get a = -4 or a = 1.\r<BR>\n" );
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document.write( "you are basically simplifying it and combining like terms and you are left with a quadratic equation which you factor in the usual ways.\r<BR>\n" );
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