document.write( "Question 1098069: Doreen and Irena plan to leave their houses at the same time, roller
\n" ); document.write( "blade towards each other, and meet for lunch after 2 hours on the road.
\n" ); document.write( "Doreen can maintain a speed of 2 miles per hour, which is 40% of Irena's
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\n" ); document.write( "\n" ); document.write( "I don't know how to solve using liner equations?
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Algebra.Com's Answer #712464 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
rate * time = distance is the basic formula to use for this type of problem.\r
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\n" ); document.write( "\n" ); document.write( "they are both skating for 2 hours when they meet.\r
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\n" ); document.write( "\n" ); document.write( "doreen skates at 2 miles per hour.\r
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\n" ); document.write( "\n" ); document.write( "this is 40% of irena's rate.\r
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\n" ); document.write( "\n" ); document.write( "if we let x = irena's speed, then 2 = .40 * x\r
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\n" ); document.write( "\n" ); document.write( "solve for x to get x = 2 / .40 = 5 miles per hour.\r
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\n" ); document.write( "\n" ); document.write( "doreen skates at 2 miles per hour.\r
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\n" ); document.write( "\n" ); document.write( "irena skates at 5 miles per hour.\r
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\n" ); document.write( "\n" ); document.write( "2/5 = .4 = 40% so we got the speeds right for doreen and irena.\r
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\n" ); document.write( "\n" ); document.write( "rate * time = distance is the basic formula to use.\r
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\n" ); document.write( "\n" ); document.write( "in 2 hours, doreen skates 2 * 2 = 4 miles towards irena.\r
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\n" ); document.write( "\n" ); document.write( "in 2 hours, irena skates 5 * 2 = 10 miles towards doreen.\r
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\n" ); document.write( "\n" ); document.write( "the distance between them has to be 14 miles.\r
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